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ammonium dose

hasan66

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Hi, when I dose calcium ammonium nitrate with 1 ppm into a 100 liter tank, how many ppm ammonium do I give?
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Hi all,
Hi, when I dose calcium ammonium nitrate with 1 ppm into a 100 liter tank, how many ppm ammonium do I give?
0.02 mg/L ammonium
The maths for this is simple enough, you just need the "1% ammonium (NH4)" from <"the packaging"> and you know straight away that you have added a very small amount of Total Ammoniacal Nitrogen (TAN).

If you want the formula (and it is the <"same process for any compound">):
  • The Relative Molecular Mass (RMM) of the calcium ammonium nitrate (5Ca(NO3)2.NH4NO3.10H2O), which in this case is 1081 (the extra mass is the ".10H2O", the <"water of crystallization">) and
  • the RMM of NH4, (using the <"RAM of the elements">) and N =14 & (1 * 4) = 18 and then
  • 18 / 1081 = 0.017 = 1.7% NH4, after that, because your tank is 100 litres, we are just into the powers of 10.
  • 1.7 / 100 = 0.017 and that is rounded to "0.02 mg / L"
cheers Darrel
 
Last edited:
Herkese selamlar,


Bunun matematiği yeterince geniş; yalnızca <" ambalajdan "> "%1 amonyum (NH4)" parçalarının yeterli ve çok az miktarda TAN eklediğinizi hemen anlarsınız.

Formülü (ve bu <" herhangi bir organik için aynı işlemdir ">):
  • Kalsiyum amonyum nitratın (5Ca(NO3)2. NH4 NO3.10H2O) Bağıl Moleküler Kütlesi (RMM), bu durumda 1081'dir (ekstra kütle ".10H2O " , <" kristalleşme suyu "> ) Ve
  • NH4'ün RMM'si (<" "> elemanlarının RAM'i yoluyla ) ve N =14 & (1 * 4) = 18 ve sonra
  • 18 / 1081 = 0,017 = %1,7 NH4, bundan sonra tankınız 100 litre olduğu için 10'un kuvvetlerine ulaştı.
  • 1,7/100 = 0,017 olup "0,02 mg/L"ye yuvarlanır
şerefe Darrel
 
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