X3NiTH
Member
- Joined
- 13 Apr 2014
- Messages
- 1,647
This is why I’m an engineer and not a chemist.
So basically I’ve made a solution of poorly soluble calcium sulphate and dissolved magnesium chloride? Some of the calcium chloride must have stayed in solution though as there’s more of it. So it’s actually a ratio something like:
2 parts CaCl2 : 1 part CaSO4 (insoluble) : 1 part MgCl2
Assuming the limits of solubility were not reached. Am I correct?
Close enough, of that 1 part CaSO4, 2.6g/L is in solution.